please explain also the solution

Additional Question Twenty-eight percent of US households have dogs, 21% have cats, and 10% have both a dog anda cat. a) What proportion has either a dog or a cat? Only a cat? Only a dog? b) What is the probability that a household has only one pet cat or dog? c) What is the probability that a household has neither a cat nor a dog? d) If a household has a cat, what is the probability that it also has a dog? e) If a household does not have a dog, what is the likelihood that it has a cat? - 124 Ch.1

### Answer Preview

Let A be the event that a household has a dog and B be the event that a household has a cat. Thus, P(A) = 0.28, P(B) = 0.21, P(AB) = 0.10, P(AB) = P(A) + P(B) - P(AB) = 0.28 + 0.21 - 0.

# Get Answer Now

Buy (USD $9.00)